Python Interviews

= Modulus Operator =

n % k == 0
 * Check whether a number is divisible by another number using the modulus operator, %

= Open a file = f=open('text.txt','r') l=f.readlines for i in l:    print(i.strip('\n'))

= List Comprehension =

[x**2 for x in range(1,11) if x % 2 == 1] [x for x in range(1,11) if x % 2 == 0]

= Slicing Operator = [start : stop : steps]

= Floor Division = 10//5 = 2 10.0//5.0 = 2.0 10.0//4 = 2.0 10.0//7 = 1.0
 * Floor Division operator used for dividing two operands with the result as quotient showing only digits before the decimal point:

= List vs. Tuple= List is mutable while the Tuple is not. A tuple is allowed to be hashed. E.g: using it as a key for dictionaries.

List: a = [1,3,6] Tuple: b = (1,4,8)

= Lambda vs. def = Def can hold multiple expressions while lambda is a uni-expression function. Def generates a function and designates a name to call it later. Lambda forms a function object and returns it. Def can have a return statement. Lambda can’t have return statements. Lambda supports to get used inside a list and dictionary.

= Optional statements in try-except block = “else” clause: It is useful if you want to run a piece of code when the try block doesn’t create an exception. “finally” clause: It is useful when you want to execute some steps which run, irrespective of whether there occurs an exception or not.
 * Optional statements possible inside a try-except block:

= List Operations =

Insert integer at position 5 at position 0: a.insert(0,5)

Delete the first occurrence of integer: a.remove(6)

Insert integer at the end of the list: a.append(9)

Sort the list: a.sort

Pop the last element from the list: a.pop

Pop 3rd element: list1.pop(2)

Reverse the list: a.reverse

Max of List(print runner-ups score): arr = [1,4,2,6,7,6] mx = max(arr) b = [j for j in arr if j != mx] print(max(b))

= List to Tuple Conv & Hashing = >>> a = [1,2,3,45,6,7] >>> a [1, 2, 3, 45, 6, 7]

>>> tuple(a) (1, 2, 3, 45, 6, 7)

>>> hash(tuple(a)) 1409902629973635913

= Eval Function =

You are given a polynomial of a single indeterminate (or variable),. You are also given the values of and. Your task is to verify if.

Input: 1 4 x**3 + x**2 + x + 1

a = (input).split x = int(a[0]) k = int(a[1])

print (eval(input) == k)
 * 1) Sol 1:

print eval(raw_input) == k
 * 1) Python 2:

f = lambda x:eval(input) print (f(x) == k)
 * 1) Sol 2:

= Swap Case =

Python has built-in string validation methods for basic data. It can check if a string is composed of alphabetical characters, alphanumeric characters, digits, etc.

str.isalnum checks if all the characters of a string are alphanumeric (a-z, A-Z and 0-9).

>>> print 'ab123'.isalnum True

str.isalpha checks if all the characters of a string are alphabetical (a-z and A-Z).

>>> print 'abcD'.isalpha True

str.isdigit checks if all the characters of a string are digits (0-9).

>>> print '1234'.isdigit True

str.islower checks if all the characters of a string are lowercase characters (a-z).

>>> print 'abcd123#'.islower True

str.isupper checks if all the characters of a string are uppercase characters (A-Z).

>>> print 'ABCD123#'.isupper True

def swap_case(s): a = "" for i in s:     if i.isupper: a += i.lower elif i.islower: a += i.upper else: a += i   return a

if __name__ == '__main__': s = input result = swap_case(s) print(result)

print ''.join([i.lower if i.isupper else i.upper for i in raw_input])

def swap_case(s): a = "" for let in s:       if let.isupper == True: a+=(let.lower) else: a+=(let.upper) return a

print raw_input.swapcase print(input.swapcase)

= Arrays & Reverse it = >>> input ="1 2 3 4 -8 -10"

>>> arr = input.split(' ') >>> arr ['1', '2', '3', '4', '-8', '-10']

>>> arr[::-1] ['-10', '-8', '4', '3', '2', '1']

= Regex =

Positive lookahead    (?=REGEX_1)REGEX_2     (?=regex)      t(?=s) matches the second t in streets. Negative lookahead    (?!REGEX_1)REGEX_2     (?!regex)      t(?!s) matches the first t in streets. Positive lookbehind                          (?<=regex)     (?<=s)t matches the first t in streets. Negative lookbehind                          (?<!regex)     (?<!s)t matches the second t in streets.

= Sum Function =

lst = [] num = int(input('How many numbers: ')) for n in range(num): numbers = int(input('Enter number ')) lst.append(numbers) print("Sum of elements in given list is :", sum(lst))

= Convert Numeral System =

for i in range(0,10): print(i, oct(i), hex(i), bin(i))

for i in range(0,10): print(i, oct(i)[2:], hex(i)[2:].upper, bin(i)[2:])

= Justify Text =

pyformat.info

text.rjust(3,' ') text.ljust(3,' ') text.center(3,' ')